Diagonal Parabolas

When I was taking Geometry and learning about parabolas, I asked my teacher what the equation was for diagonal parabolas. To my disappointment, he did not give me a satisfying answer. He told me that I would learn how to find those in college, but for now, all I needed to know were the equations for parabolas that opened exclusively vertically or horizontally. I was somewhat upset when I derived the equation for a diagonal parabola using algebra I learned my sophomore year in high school.

A parabola is the set of points that are equidistant from a separate point, called a focus, and a line, called a directrix.

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If I want the parabola to open up or down, I make the directrix a horizontal line. If I want the parabola to open sideways, I make the directrix a vertical line. If I made the directrix a diagonal line, then I could find a diagonal parabola by utilizing the distance formula.

The definition of a parabola is that at any one point, it is equidistant from a point and a line. I will make a point on the parabola (x,y) and set the distances from (x,y) to the directrix and to the focus equal to each other.PSX_20180913_204953

The left side of the equation is just the distance between two points. The right side is the formula for the distance between a point and a line. I pinky-promise I will derive that formula later, but I’m not going to do it here. I will make the equation of the line x + y = 0 so the calculations aren’t excessively painful. I’m not going to find the generic equation for a diagonal parabola; I just want one diagonal parabola.

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At the end, I get an equation that’s different from the parabola formula I’m used to in geometry. This is mostly because I cannot get this equation to express y as a function of x or vice versa. I can show a vertical parabola as a function of x because for every x value, there is only one y value. That’s the definition of a function. Diagonal parabolas cannot be functions because there are always two y values for each x value (except for one point at the beginning of the parabola).

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That ticks me off because I spent twenty minutes trying to find a functional diagonal parabola before it hit me. I wasted half my study hall for nothing.

I wouldn’t have done any of this if my Geometry teacher had just said that diagonal parabolas would take some more complicated algebra. Instead, I felt the need to figure it out before I went away to college. CDR, if you ever read this, I want you to know that the whole point of this post was to prove you wrong.

Update: this can be written as two functions. I can use the quadratic formula to solve for y. Thank you, Potter.

https://amsi.org.au/ESA_Senior_Years/SeniorTopic2/2a/2a_2content_10.html

 

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